Solve x^2-2x+5 = 0

Solve ax² + bx + c = 0 using the quadratic formula with discriminant analysis.

Equation
Answer
x = 1 ± 2i

x2-2x+5=0

Solve using the quadratic formula since this quadratic does not factor nicely:

Step 1 — Identify the coefficients

Compare with the standard form ax² + bx + c = 0:

a = 1, b = −2, c = 5

Step 2 — Substitute into the quadratic formula

x = (−b ± b2 − 4ac) / 2a

x = (2 ± (-2)2 − 4(1)(5)) / 2(1)

x = (2 ± 4 − 20) / 2

x = (2 ± -16) / 2

Step 3 — Evaluate the discriminant

Δ = b² − 4ac = 4 − 20 = -16

Since Δ = -16 is negative, the solutions are complex:

x = 1 ± 2i

x = 1 ± 2i

How to solve x^2-2x+5 = 0

To solve x^2-2x+5 = 0, we can try factoring, use the quadratic formula, or complete the square. The solution is x = 1 ± 2i.

This is a second-degree quadratic equation — the highest power of the variable is 2. Quadratic equations can have two real roots, one repeated root, or two complex roots.

Frequently asked questions

What is the answer to x^2-2x+5 = 0?
The answer is x = 1 ± 2i.

What method is used?
factoring when possible, or the quadratic formula x = (−b ± √(b²−4ac)) / 2a. The discriminant b²−4ac determines the number and type of solutions.

How do I verify this?
Substituting the solution(s) back into x^2-2x+5 = 0 confirms both sides are equal.

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