Solve x^2-2x+5 = 0
Solve ax² + bx + c = 0 using the quadratic formula with discriminant analysis.
x2-2x+5=0
Solve using the quadratic formula since this quadratic does not factor nicely:
Compare with the standard form ax² + bx + c = 0:
a = 1, b = −2, c = 5
x = (−b ± √b2 − 4ac) / 2a
x = (2 ± √(-2)2 − 4(1)(5)) / 2(1)
x = (2 ± √4 − 20) / 2
x = (2 ± √-16) / 2
Δ = b² − 4ac = 4 − 20 = -16
Since Δ = -16 is negative, the solutions are complex:
x = 1 ± 2i
x = 1 ± 2i
How to solve x^2-2x+5 = 0
To solve x^2-2x+5 = 0, we can try factoring, use the quadratic formula, or complete the square. The solution is x = 1 ± 2i.
This is a second-degree quadratic equation — the highest power of the variable is 2. Quadratic equations can have two real roots, one repeated root, or two complex roots.
Frequently asked questions
What is the answer to x^2-2x+5 = 0?
The answer is x = 1 ± 2i.
What method is used?
factoring when possible, or the quadratic formula x = (−b ± √(b²−4ac)) / 2a. The discriminant b²−4ac determines the number and type of solutions.
How do I verify this?
Substituting the solution(s) back into x^2-2x+5 = 0 confirms both sides are equal.