Solve x^2+2x-8 = 0
Solve ax² + bx + c = 0 using the quadratic formula with discriminant analysis.
x2+2x-8=0
Solve by factoring the quadratic and applying the zero product property:
We need two numbers that multiply to -8 (the constant term) and add to 2 (the coefficient of x):
4 × -2 = -8 and 4 + (-2) = 2
Write the factored form using these numbers:
(x - 2)(x + 4) = 0
If a product equals zero, at least one of the factors must be zero. Set each factor equal to zero and solve:
x − 2 = 0 → x = 2
x + 4 = 0 → x = −4
x = -4, 2
How to solve x^2+2x-8 = 0
To solve x^2+2x-8 = 0, we can try factoring, use the quadratic formula, or complete the square. The solution is x = -4, 2.
This is a second-degree quadratic equation — the highest power of the variable is 2. Quadratic equations can have two real roots, one repeated root, or two complex roots.
Frequently asked questions
What is the answer to x^2+2x-8 = 0?
The answer is x = -4, 2.
What method is used?
factoring when possible, or the quadratic formula x = (−b ± √(b²−4ac)) / 2a. The discriminant b²−4ac determines the number and type of solutions.
How do I verify this?
Substituting the solution(s) back into x^2+2x-8 = 0 confirms both sides are equal.