Solve x^2+2x-8 = 0

Solve ax² + bx + c = 0 using the quadratic formula with discriminant analysis.

Equation
Answer
x = -4, 2

x2+2x-8=0

Solve by factoring the quadratic and applying the zero product property:

Step 1 — Factor the quadratic

We need two numbers that multiply to -8 (the constant term) and add to 2 (the coefficient of x):

4 × -2 = -8 and 4 + (-2) = 2

Write the factored form using these numbers:

(x - 2)(x + 4) = 0

Step 2 — Apply the zero product property

If a product equals zero, at least one of the factors must be zero. Set each factor equal to zero and solve:

x − 2 = 0 → x = 2

x + 4 = 0 → x = −4

x = -4, 2

-4 -2 2 -10 -5 5 10 15 x = -1 (-4, 0) (2, 0) vertex (-1, -9) (0, -8)

How to solve x^2+2x-8 = 0

To solve x^2+2x-8 = 0, we can try factoring, use the quadratic formula, or complete the square. The solution is x = -4, 2.

This is a second-degree quadratic equation — the highest power of the variable is 2. Quadratic equations can have two real roots, one repeated root, or two complex roots.

Frequently asked questions

What is the answer to x^2+2x-8 = 0?
The answer is x = -4, 2.

What method is used?
factoring when possible, or the quadratic formula x = (−b ± √(b²−4ac)) / 2a. The discriminant b²−4ac determines the number and type of solutions.

How do I verify this?
Substituting the solution(s) back into x^2+2x-8 = 0 confirms both sides are equal.

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