Factor x^3-6x^2+11x-6

Factor polynomials completely: trinomials, difference of squares, sum/difference of cubes.

Expression
Answer
(x - 3)(x - 2)(x - 1)

To factor x^3-6x^2+11x-6, look for patterns like grouping, difference of squares, or rational roots.

x3-6x2+11x-6

Step 1 — List possible rational roots

By the Rational Root Theorem, any rational root p/q must have p dividing the constant term and q dividing the leading coefficient:

Factors of constant (6): ±{1, 2, 3, 6}

Factors of leading (1): ±{1}

Candidates: 1, -1, 2, -2, 3, -3, 6, -6

Step 2 — Test x = 1 and divide

Substitute x = 1 into the polynomial:

f(1) = (1)3 − 6(1)2 + 11(1) − 6 = 0

f(1) = 0 ✓ → (x − 1) is a factor

Perform synthetic division by (x − 1):

[1 | -6 | 11 | -6] ÷ (1) → [1 | -5 | 6]

Quotient: x2 − 5x + 6

Step 3 — Factor the remaining quadratic

Factor x^2 − 5x + 6:

= (x - 3)(x - 2)

Step 4 — Write the complete factored form

= (x - 3)(x - 2)(x - 1)

(x - 3)(x - 2)(x - 1)

How to factor x^3-6x^2+11x-6

To factor x^3-6x^2+11x-6, identify the type of polynomial and apply the appropriate technique. The factored form is (x - 3)(x - 2)(x - 1).

This is a polynomial factoring problem — we break a polynomial into a product of simpler expressions. Common methods include GCF extraction, difference of squares, and trinomial factoring.

Frequently asked questions

What is the answer to x^3-6x^2+11x-6?
The answer is (x - 3)(x - 2)(x - 1).

What method is used?
identifying the polynomial type and applying the matching technique — GCF, trinomial factoring, difference of squares, or special cube formulas.

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